# eachRight (:R)

**Syntax**

eachRight(func, X, Y, [consistent=false])

or

X <operator>:R Y (when consistent = false)

or

X <operator>:RC Y (when consistent = true)

or

func:R(X, Y, [consistent=false])

**Arguments**

func is a binary function.

X/ Y is a vector/matrix/table/dictionary.

consistent is a Boolean value. The default value is false, indicating that the data type of the result is determined by each calculation result. Otherwise, the data type of the result is the same as the data type of the first calculation result. Note that if the data forms of result are inconsistent, consistent can only be specified as false. Otherwise, an error will be reported.

**Details**

Calculate *func(X, Y(i))* for each element of *Y*.

Y(i) is each element when

*Y*is a vector.Y(i) is each column when

*Y*is a matrix.Y(i) is each row when

*Y*is a table.Y(i) is each value when

*Y*is a dictionary.

If the function/operator supports vector operation and the input itself is a vector, we should avoid the `eachRight`

template and use the vector function/operator directly instead for better performance.

**Examples**

`eachRight`

with 2 vectors:

```
$ x = 4 3 2 1
$ y = 3 0 6;
$ eachRight(add, x, y);
```

3 |
0 |
6 |
---|---|---|

7 |
4 |
10 |

6 |
3 |
9 |

5 |
2 |
8 |

4 |
1 |
7 |

```
$ x pow :R y;
```

3 |
0 |
6 |
---|---|---|

64 |
1 |
4096 |

27 |
1 |
729 |

8 |
1 |
64 |

1 |
1 |
1 |

`eachRight`

with a matrix and a vector:

```
$ x=1..6$2:3;
$ x;
```

col1 |
col2 |
col3 |
---|---|---|

1 |
3 |
5 |

2 |
4 |
6 |

```
$ 1 1 ** :R x;
[3,7,11]
```

`eachRight`

with 2 matrices:

```
$ y=6..1$3:2;
$ y;
```

col1 |
col2 |
---|---|

6 |
3 |

5 |
2 |

4 |
1 |

```
$ eachRight(**, x, y);
(#0
--
41
56
,#0
--
14
20
)
```

`eachRight`

with a dictionary and a vector:

```
$ d=dict(`a`b`c, [[1, 2, 3],[4, 5, 6], [7, 8, 9]])
$ eachRight(add,10 20 30,d)
a->[11,22,33]
b->[14,25,36]
c->[17,28,39]
```