slice

Syntax

slice(obj, index)

or

slice(obj, rowIndex, [colIndex])

Arguments

obj is a matrix or a table.

Details

For slice(obj, index):

• If obj is a matrix:

  • If index is a scalar, return a vector indicating a column.

  • If index is a vector or a pair, return a matrix of selected columns.

• If obj is a table:

  • If index is a scalar, return a dictionary indicating a row.

  • If index is a vector or a pair, return a table of selected rows.

For slice(obj, rowIndex, [colIndex]):

• If obj is a matrix:

  • If rowIndex and colIndex are both scalars, return a scalar indicating the value of specified element of the matrix.

  • If rowIndex and colIndex are both vectors or pairs, return a matrix of selected rows and columns.

• If obj is a table:

  • If rowIndex and colIndex are both scalars, return a scalar indicating the value of specified element of the table.

  • If rowIndex and colIndex are both vectors or pairs, return a table of selected rows and columns.

To get a particular row or column from a table, consider using function col or row.

Examples

If obj is a matrix:

$ m=1..9$3:3
m.slice(0);
[1,2,3]

$ m.slice([0]);

#0
1
2
3

$ m.slice(0:2);

#0	#1
1	4
2	5
3	6

$ m.slice(0 2);

#0	#1
1	7
2	8
3	9

$ m.slice(0,1);
4

$ m.slice(0 1,0 1);

#0	#1
1	4
2	5

$ m.slice(1:2,1:2);

#0
5

If obj is a table:

$ t=table(`A`B`C as sym,2018.01.01..2018.01.03 as date,10 48 5 as val)
t.slice(0);
val->10
date->2018.01.01
sym->A
t.slice([0]);

sym	date	val
A	2018.01.01	10

$ t.slice(0 1);

sym	date	val
A	2018.01.01	10
B	2018.01.02	48

$ t.slice(0:1);

sym	date	val
A	2018.01.01	10

$ t.slice(0,1);
2018.01.01

$ t.slice(0 1,0 1);

sym	date
A	2018.01.01
B	2018.01.02

$ t.slice(1:2,1:2);

date
2018.01.02