# join!

Syntax

join!(X, Y)

Arguments

X is a vector/matrix/table.

Y is a scalar/vector/matrix/table.

If X is a vector, Y is a scalar/vector; if X is a matrix, Y is a vector/matrix; if X is a table, Y is a vector/table.

Details

Merge X and Y, and assign the result to X. The resulting object has the same data type as X.

Examples

If X is a vector, Y must be a scalar/vector. The result is a vector.

```\$ x=[1,2,3]
\$ x.join!(4)
\$ x;
[1,2,3,4]

\$ x.join!(5 6 7)
\$ x;
[1,2,3,4,5,6,7]
```

If X is a matrix, Y must be a vector/matrix with the same number of rows as X. The result is a matrix with the same number of rows as X.

```\$ x=1..6\$2:3
\$ join!(x, [7,8])
\$ x;
```

#0

#1

#2

#3

1

3

5

7

2

4

6

8

```\$ x.join!(9..12\$2:2)
\$ x;
```

#0

#1

#2

#3

#4

#5

1

3

5

7

9

11

2

4

6

8

10

12

If X is a table, Y must be a table or a vector with the same number of rows as X. The result is a table with the same number of rows as X.

```\$ a=table(1..3 as x, 4.5 6.7 8.5 as y);
\$ a;
```

x

y

1

4.5

2

6.7

3

8.5

```\$ b=table(700 500 800 as z);
\$ b;
```

z

700

500

800

```\$ join!(a,b);
\$ a;
```

x

y

z

1

4.5

700

2

6.7

500

3

8.5

800

```\$ a=table(1..3 as x, `IBM`C`AAPL as y);
\$ b=table(172.3 25 106.5 as z);
\$ a.join!(b);
\$ a;
```

x

y

z

1

IBM

172.3

2

C

25

3

AAPL

106.5